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printneatly.cpp
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printneatly.cpp
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/*
Problem : Given a text of n words, and an integer M, the length in characters of a line, print the text neatly to minimize
the number of extra spaces at the end of the lines.
*/
#include <string>
#include <iostream>
#include <vector>
#include <cmath>
#include <climits>
#include <stack>
using namespace std;
void calculateCost(vector< vector<int> >&cost,vector<string> &input,int maxWidth){
for(int k=0;k<input.size();k++){
//for one word on a given line
cost[k][k]=maxWidth-input[k].length();
for(int r=k+1;r<input.size();r++){
//for more than one word on a given line, -1 for every word needs a space between them
cost[k][r]=cost[k][r-1]-input[r].length()-1;
}
}
for(int k=0;k<input.size();k++){
for(int r=0;r<input.size();r++){
//invalid word placement if it is greater than the max width
//+1 since an extra space has been given, 3 words should be 2 spaces only
cost[k][r]++;
if(cost[k][r]<0)
cost[k][r]=INT_MAX;
//other wise give it a penalty of x^2
else
cost[k][r]=pow(cost[k][r],2);
}
}
}
void print(vector< vector<int> >&cost,vector<string> &input){
//find the best placement of the strings on each line, min penalty
vector<int> minPenalty(cost.size(),0);
vector<int> backtracking(cost.size(),0);
for(int k=cost.size()-1;k>=0;k--){
minPenalty[k]=cost[k][cost.size()-1];
backtracking[k]=cost.size();
for(int r=cost.size()-1;r>k;r--){
if(cost[k][r-1]!=INT_MAX){
if(minPenalty[k]>minPenalty[r]+cost[k][r-1]){
minPenalty[k]=minPenalty[r]+cost[k][r-1];
backtracking[k]=r;
}
}
}
}
//use backtracking to print the words with the lowest penalty of spaces
for(int k=0;k<backtracking.size();k++)
{
if(k==0)
{
for(int r=0;r<backtracking[0];r++)
{
cout<<input[r]<<" ";
}
if(k+1<backtracking.size()){
if(backtracking[0]!=backtracking[k+1])
cout<<endl;
}
}
else{
for(int r=backtracking[k-1];r<backtracking[k];r++)
{
cout<<input[r]<<" ";
}
if(backtracking[k]!=backtracking[k-1])
cout<<endl;
}
}
}
int main(){
int inputSize;
cin>>inputSize;
vector<string> input(inputSize);
int maxWidth;
cin>>maxWidth;
for(int k=0;k<inputSize;k++)
cin>>input[k];
//cost printing string x[0] to x[i], number of empty spaces on a given line
vector< vector<int> > cost(inputSize, vector<int>(inputSize, 0));
calculateCost(cost,input,maxWidth);
print(cost,input);
}