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In the steps leading to Equation (1.2.3) in Example 1.2.6, we establish that x^2+x-1 could be negative, yet also state that
x^2+x-1 < 5 implies
1/(x^2+x-1) > 1/5.
We need to add abs. values to some of these steps.
The text was updated successfully, but these errors were encountered:
In the steps leading to Equation (1.2.3) in
Example 1.2.6, we establish that x^2+x-1 could be negative, yet also state that
x^2+x-1 < 5 implies
1/(x^2+x-1) > 1/5.
We need to add abs. values to some of these steps.
The text was updated successfully, but these errors were encountered: