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Shubham:Electrical Task 1 #34

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Binary file added electrical/Shubhamtask1/Magnificent Waasa.png
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11 changes: 11 additions & 0 deletions electrical/Shubhamtask1/read.md
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public link-https://www.tinkercad.com/things/gDDdAoHANiJ-magnificent-waasa/editel?sharecode=D0rq9lTsbbO935-sBFrH3FerTkwvC51C23d-xkqQTMM

Explanation:

Initially the circuit without diodes consists of two resistance R1 and R2 and capacitor C . Then t1(oscillator charge ) is given
by t1=0.693(R1+R2)C and t2 (capacitor discharge) by t2=0.693R2C.
Thereby total time T=t1+t2 and duty=t1/T*100.
After connecting diode capacitor charges through R1 as R2 is shorted while during discharge capacitor dischages through R2.
Thus duty reduces to R1/(R1+R2)
on choosing R1=R2 duty can be made 50%.