给定一个只包括 '('
,')'
,'{'
,'}'
,'['
,']'
的字符串,判断字符串是否有效。
有效字符串需满足:
左括号必须用相同类型的右括号闭合。 左括号必须以正确的顺序闭合。 注意空字符串可被认为是有效字符串。
示例 1:
输入: "()"
输出: true
示例 2:
输入: "()[]{}"
输出: true
示例 3:
输入: "(]"
输出: false
示例 4:
输入: "([)]"
输出: false
示例 5:
输入: "{[]}"
输出: true
class Solution:
def isValid(self, s: str) -> bool:
dic = {")": "(",
"]": "[",
"}": "{"}
line = []
for char in s:
if char in dic:
if not line or line.pop() != dic[char]:
return False
else:
line.append(char)
return not line
将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
class Solution:
def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:
if not l1 or not l2:
return l1 if l1 else l2
if l1.val <= l2.val:
first = l1
head = l1
second = l2
else:
first = l2
head = l2
second = l1
while head:
# 碰到大于等于的数 才要插入到前面
if head.val > second.val:
head.val, second.val = second.val, head.val
temp = head.next
head.next = second
second = second.next
head.next.next = temp
# second, head.next, second.next = second.next, second, head.next
if head.next is None:
head.next = second
break
head = head.next
if second is None:
break
return first