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Table: Employee
+-------------+------+ | Column Name | Type | +-------------+------+ | id | int | | salary | int | +-------------+------+ id is the primary key (column with unique values) for this table. Each row of this table contains information about the salary of an employee.
Write a solution to find the nth
highest salary from the Employee
table. If there is no nth
highest salary, return null
.
The result format is in the following example.
Example 1:
Input: Employee table: +----+--------+ | id | salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+ n = 2 Output: +------------------------+ | getNthHighestSalary(2) | +------------------------+ | 200 | +------------------------+
Example 2:
Input: Employee table: +----+--------+ | id | salary | +----+--------+ | 1 | 100 | +----+--------+ n = 2 Output: +------------------------+ | getNthHighestSalary(2) | +------------------------+ | null | +------------------------+
import pandas as pd
def nth_highest_salary(employee: pd.DataFrame, N: int) -> pd.DataFrame:
unique_salaries = employee.salary.unique()
if len(unique_salaries) < N:
return pd.DataFrame([np.NaN], columns=[f"getNthHighestSalary({N})"])
else:
salary = sorted(unique_salaries, reverse=True)[N - 1]
return pd.DataFrame([salary], columns=[f"getNthHighestSalary({N})"])
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
SET N = N - 1;
RETURN (
# Write your MySQL query statement below.
SELECT (
SELECT DISTINCT salary
FROM Employee
ORDER BY salary DESC
LIMIT 1 OFFSET N
)
);
END