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Table: Orders
+-------------+------+ | Column Name | Type | +-------------+------+ | minute | int | | order_count | int | +-------------+------+ minute is the primary key for this table. Each row of this table contains the minute and number of orders received during that specific minute. The total number of rows will be a multiple of 6.
Write a query to calculate total orders within each interval. Each interval is defined as a combination of 6
minutes.
- Minutes
1
to6
fall within interval1
, while minutes7
to12
belong to interval2
, and so forth.
Return the result table ordered by interval_no in ascending order.
The result format is in the following example.
Example 1:
Input: Orders table: +--------+-------------+ | minute | order_count | +--------+-------------+ | 1 | 0 | | 2 | 2 | | 3 | 4 | | 4 | 6 | | 5 | 1 | | 6 | 4 | | 7 | 1 | | 8 | 2 | | 9 | 4 | | 10 | 1 | | 11 | 4 | | 12 | 6 | +--------+-------------+ Output: +-------------+--------------+ | interval_no | total_orders | +-------------+--------------+ | 1 | 17 | | 2 | 18 | +-------------+--------------+ Explanation: - Interval number 1 comprises minutes from 1 to 6. The total orders in these six minutes are (0 + 2 + 4 + 6 + 1 + 4) = 17. - Interval number 2 comprises minutes from 7 to 12. The total orders in these six minutes are (1 + 2 + 4 + 1 + 4 + 6) = 18. Returning table orderd by interval_no in ascending order.
# Write your MySQL query statement below
WITH
T AS (
SELECT
minute,
SUM(order_count) OVER (
ORDER BY minute
ROWS 5 PRECEDING
) AS total_orders
FROM Orders
)
SELECT minute / 6 AS interval_no, total_orders
FROM T
WHERE minute % 6 = 0;
SELECT
FLOOR((minute + 5) / 6) AS interval_no,
SUM(order_count) AS total_orders
FROM Orders
GROUP BY 1
ORDER BY 1;