fizzbuzz.py

'''
Write a program that prints the numbers from 1 to 100.
But for multiples of three print "Fizz" instead of the
number and for the multiples of five print "Buzz". For
numbers which are multiples of both three and five
print "FizzBuzz".

Sample output:
1, 2, Fizz, 4, Buzz, Fizz, 7, 8, Fizz, Buzz, 11, Fizz, 13, 14, FizzBuzz
'''


def fizzbuzz(n: int):
    ret = ''
    if n % 3 == 0:
        ret += 'Fizz'
    if n % 5 == 0:
        ret += 'Buzz'
    if n % 3 != 0 and n % 5 != 0:
        ret = str(n)
    return ret


def fizzbuzz_without_if_rayan(n: int):
    return (n % 3 == 0) * 'Fizz' + (n % 5 == 0) * 'Buzz' + (n % 3 != 0 and n % 5 != 0) * str(n)


def fizzbuzz_without_if_nathan(n: int):
    ''' Implementação do algoritimo sem uso de if's que ganhou a caneca '''

    ret = ''
    while (n % 3 == 0):
        ret += 'Fizz'
        break

    while (n % 5 == 0):
        ret += 'Buzz'
        break

    while (n % 3 != 0 and n % 5 != 0):
        ret = str(n)
        break

    return ret


def main():
    numbers = [fizzbuzz(n) for n in range(1, 101)]
    print(*numbers, sep='\n')


if __name__ == '__main__':
    main()