Divide correlations by standard deviation

[jdkent]

Describe the bug
In the original Rissman (2004) paper, the fisher's z -transformed correlation coefficients were divided by their "known" standard deviation.

The transformed correlation coefficients were then
divided by their known standard deviation (1 / sqrt(N-3) , where N is
the number of data points used to compute the correlation
coefficient) to yield z scores.

To Reproduce
Use NiBetaSeries to create correlations

Expected behavior
The correlations should be normalized

Desktop (please complete the following information):
N/A

nibetaseries version
v0.4.3

Additional context
N/A