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107. 二叉树的层次遍历 II.md

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47 lines (42 loc) · 904 Bytes

给定一个二叉树,返回其节点值自底向上的层次遍历。 (即按从叶子节点所在层到根节点所在的层,逐层从左向右遍历)

例如: 给定二叉树 [3,9,20,null,null,15,7],

    3
   / \
  9  20
    /  \
   15   7

返回其自底向上的层次遍历为:

[
  [15,7],
  [9,20],
  [3]
]
/**
 * Definition for a binary tree node.
 * function TreeNode(val) {
 *     this.val = val;
 *     this.left = this.right = null;
 * }
 */
/**
 * @param {TreeNode} root
 * @return {number[][]}
 */
var levelOrderBottom = function(root) {
    if (!root) return []
    const res = []
    function f(node, deep) {
        res[deep - 1] ? res[deep - 1].push(node.val) : res[deep - 1] = [node.val]
        node.left && f(node.left, deep + 1)
        node.right && f(node.right, deep + 1)
    }
    f(root, 1)
    return res.reverse()
};