将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
solution:
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var mergeTwoLists = function (l1, l2) {
function listNode(val) {
this.val = val;
this.next = null;
}
function fillNode(nodeList, val) {
if (nodeList.next === null) {
nodeList.next = {
val: val,
next: null
}
} else {
return fillNode(nodeList.next, val)
}
}
if (l1 === null && l2 === null) {
return null
} else if (l1 === null) {
return l2
} else if (l2 === null) {
return l1
} else {
var pre = l1,
aft = l2
var result
if (pre.val < aft.val) {
result = new listNode(pre.val)
pre = pre.next
} else {
result = new listNode(aft.val)
aft = aft.next
}
while (pre !== null || aft !== null) {
if (pre !== null && aft !== null && pre.val < aft.val) {
fillNode(result, pre.val)
pre = pre.next
} else if (pre !== null && aft !== null && pre.val >= aft.val) {
fillNode(result, aft.val)
aft = aft.next
} else if (pre === null) {
fillNode(result, aft.val)
aft = aft.next
} else {
fillNode(result, pre.val)
pre = pre.next
}
}
return result
}
};