Calling __next__ before __iter__ on Paginator gives error

[PeterLombaers]

The paginator class implements both __iter__ and __next__, but if you call __next__ before __iter__ you get an error:

import pyalex
pager = pyalex.Works().paginate()
next(pager)

gives:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/peter/venv/lib/python3.10/site-packages/pyalex/api.py", line 137, in __next__
    if self._next_value is None or self._is_max():
  File "/home/peter/venv/lib/python3.10/site-packages/pyalex/api.py", line 132, in _is_max
    if self.n_max and self.n >= self.n_max:
AttributeError: 'Paginator' object has no attribute 'n'

Given that the name of the class is Paginator I expected it to be an iterator (i.e., allow calling __next__).