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+/* Author :  JaiSehgal007 */
+
+/* House Robber Problem III from Leetcode */
+
+/* Link to the Problem : https://leetcode.com/problems/house-robber-iii/ */
+
+/*
+PROBLEM DESCRIPTION:
+The thief has found himself a new place for his thievery again. There is only one entrance to this area, called root.
+Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that all houses in this place form a binary tree. It will 
+automatically contact the police if two directly-linked houses were broken into on the same night.
+Given the root of the binary tree, return the maximum amount of money the thief can rob without alerting the police.
+*/
+
+/*
+EXAMPLES TO THE PROBLEM:
+Example 1:
+Input: root = [3,2,3,null,3,null,1]
+Output: 7
+Explanation: Maximum amount of money the thief can rob = 3 + 3 + 1 = 7.
+Example 2:
+Input: root = [3,4,5,1,3,null,1]
+Output: 9
+Explanation: Maximum amount of money the thief can rob = 4 + 5 = 9.
+*/
+
+/*-------------------------------------SOLUTION---------------------------------------*/
+class Solution {
+public:
+    int robber(TreeNode* root,int &l,int &r){
+        if(!root)return 0;
+        int ll=0,lr=0,rl=0,rr=0;
+        l=robber(root->left,ll,lr);
+        r=robber(root->right,rl,rr);
+
+        return max(l+r,root->val+ll+lr+rl+rr);
+
+    }
+    int rob(TreeNode* root) {
+        int l,r;
+        return robber(root,l,r);
+    }
+};