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“因为 𝑞0 与 𝑞1 都是单位四元数,𝑞0 · 𝑞1 正好是这两个四元数在 4D 空间中夹 角的余弦值”, 这句在三维的情况下成立, 四维的情况, 是不是需要添加个证明?
谢谢!
The text was updated successfully, but these errors were encountered:
这个很简单,是把四元数当成一个4D的向量来看的, q0\cdot q1 = |q0| * |q_1| * cos<q0, q_1> 因为 是单位四元数,所以 |q0|=|q1|=1
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“因为 𝑞0 与 𝑞1 都是单位四元数,𝑞0 · 𝑞1 正好是这两个四元数在 4D 空间中夹 角的余弦值”, 这句在三维的情况下成立, 四维的情况, 是不是需要添加个证明?
谢谢!
The text was updated successfully, but these errors were encountered: