lecture_19

Mon Jul 2 09:11:42 CDT 2012

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Posion Distrobution

[k! \sim \frac{ k^k}{ e^k} \sqrt{ 2 \pi k}]

[k! k^{-e} e^{k} (2 \pi k)^{-1/2} \rightarrow 1]

[\ln k! - \frac{ 1}{ 2} \ln( 2 \pi) - \frac{ 1}{ 2} \ln k - k \ln k + k \rightarrow 0]

remember the table

         Expected         Var.
Binomial \[n p\]    \[n p (1 - p)\]
Poisson  \[\lambda\] 
Geom (p)