create an object and test value.js

// Given an array of integers, find the one that appears an odd number of times.

// There will always be only one integer that appears an odd number of times.

// Examples
// [7] should return 7, because it occurs 1 time (which is odd).
// [0] should return 0, because it occurs 1 time (which is odd).
// [1,1,2] should return 2, because it occurs 1 time (which is odd).
// [0,1,0,1,0] should return 0, because it occurs 3 times (which is odd).
// [1,2,2,3,3,3,4,3,3,3,2,2,1] should return 4, because it appears 1 time (which is odd).

function findOdd(A) {
    console.log(A)
    let object = A.reduce((arr, cur) => { arr[cur] ? arr[cur]++ : arr[cur] = 1; return arr; }, {})
    console.log(object)
    for (let property in object) {
      if (object[property] % 2 != 0) {
        return Number(property)
      }
    }
  }

  //even better
  const cakes = (needs, has) => Math.min(
    ...Object.keys(needs).map(key => Math.floor(has[key] / needs[key] || 0))
  )