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24. Swap Nodes in Pairs.cpp
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24. Swap Nodes in Pairs.cpp
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/*
Given a linked list, swap every two adjacent nodes and return its head.
You may not modify the values in the list's nodes, only nodes itself may be changed.
Example:
Given 1->2->3->4, you should return the list as 2->1->4->3.
New_Head is used to record the head pointer,
temp to store the next starting point,
prev to store the last point in the pair
Solution two using recursive
*/
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
if ( !head || !head->next ) return head;
ListNode *Head_New = head->next, *temp = head->next->next;
head->next->next = head;
head->next = temp;
ListNode *prev = head;
head = head->next;
while ( head && head->next )
{
prev->next = head->next;
temp = head->next->next;
head->next->next = head;
head->next = temp;
prev = head;
head = head->next;
}
return Head_New;
}
};
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
if ( !head || !head->next ) return head;
ListNode *t = head->next;
head->next = swapPairs( head->next->next );
t->next = head;
return t;
}
};