Strings not printing properly

[vincentabraham]

I've written the following program in main.c:

TaskHandle_t vTask1Handle = NULL;
TaskHandle_t vTask2Handle = NULL;
QueueHandle_t myQueue;

void vTask1(void* p);
void vTask2(void* p);


void vTask1(void* p)
{
    char myTxBuff[30];

    myQueue = xQueueCreate(
        1, // Size of the queue
        sizeof(myTxBuff) // Size of each block
    );
    sprintf(myTxBuff, "Message 1");
    xQueueSend(
        myQueue,
        (void*) myTxBuff,
        (TickType_t) 0
    );

    sprintf(myTxBuff, "Message 2");
    xQueueOverwrite(
        myQueue,
        (void*) myTxBuff
    );

    vTaskDelay(pdMS_TO_TICKS(1000));
    printf("Data Waiting to be read: %d\r\n", uxQueueMessagesWaiting(myQueue));

    //vTaskDelay(pdMS_TO_TICKS(1000));
    printf("Spaces Available: %d\r\n", uxQueueSpacesAvailable(myQueue));

    while(1)
    {
        ;    
    }
}

void vTask2(void* p)
{
    char myRxBuff[30];

    while(1)
    {
        vTaskDelay(pdMS_TO_TICKS(1000));
        if(myQueue != 0){
            if(xQueuePeek(myQueue, (void*)myRxBuff, (TickType_t)0)){
                printf("Data Received: %s\r\n", myRxBuff);
            }
        }
    }
}


int main(void)
{

    xTaskCreate(vTask1,             // Function that the task executes
                "Task 1",            // Name
                1024,                // Stack Size
                (void*)0,                // Parameters
                1,                  // Priority
                &vTask1Handle);      // Task Handler
    
    xTaskCreate(vTask2,             // Function that the task executes
                "Task 2",            // Name
                1024,                // Stack Size
                (void*)0,                // Parameters
                1,                  // Priority
                &vTask2Handle);      // Task Handler

    vTaskStartScheduler();
    while(1)
    {
        ;
    }
    return 0;
}

However, this is the output I get:

How could I get the strings to print properly? It seems like if there are more than one lines to print, then this happens.