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Copy pathDay57_Maximum Width of Binary Tree.py
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Day57_Maximum Width of Binary Tree.py
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# Maximum Width of Binary Tree Difficulty = Medium
# Given the root of a binary tree, return the maximum width of the given tree.
# The maximum width of a tree is the maximum width among all levels.
# The width of one level is defined as the length between the end-nodes (the leftmost and rightmost non-null nodes), where the null nodes between the end-nodes that would be present in a complete binary tree extending down to that level are also counted into the length calculation.
# It is guaranteed that the answer will in the range of a 32-bit signed integer.
# Example 1:
# Input: root = [1,3,2,5,3,null,9]
# Output: 4
# Explanation: The maximum width exists in the third level with length 4 (5,3,null,9).
# Example 2:
# Input: root = [1,3,2,5,null,null,9,6,null,7]
# Output: 7
# Explanation: The maximum width exists in the fourth level with length 7 (6,null,null,null,null,null,7).
class Solution:
def widthOfBinaryTree(self, root: Optional[TreeNode]) -> int:
if not root:
return 0
queue = deque([(root, 0)])
max_width = 0
while queue:
level_length = len(queue)
_, level_start = queue[0]
for i in range(level_length):
node, index = queue.popleft()
if node.left:
queue.append((node.left, 2*index))
if node.right:
queue.append((node.right, 2*index+1))
max_width = max(max_width, index - level_start + 1)
return max_width