From 6fe64b61745e1cf5b091bde01027c588e3d9efb9 Mon Sep 17 00:00:00 2001
From: Sathvik Bhagavan <sathvik.bhagavan@juliahub.com>
Date: Sat, 6 Jul 2024 11:49:04 +0000
Subject: [PATCH] docs: remove scatter of data points as it is in the recipe
 itself

---
 docs/src/methods.md | 42 ++++++++++++++----------------------------
 1 file changed, 14 insertions(+), 28 deletions(-)

diff --git a/docs/src/methods.md b/docs/src/methods.md
index 3762aba5..b325e7d6 100644
--- a/docs/src/methods.md
+++ b/docs/src/methods.md
@@ -22,8 +22,7 @@ This is a linear interpolation between the ends points of the interval of input
 
 ```@example tutorial
 A = LinearInterpolation(u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Quadratic Interpolation
@@ -36,8 +35,7 @@ forward-looking). It is continuous and piecewise differentiable.
 ```@example tutorial
 A = QuadraticInterpolation(u, t) # same as QuadraticInterpolation(u,t,:Forward)
 # alternatively: A = QuadraticInterpolation(u,t,:Backward)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Lagrange Interpolation
@@ -47,8 +45,7 @@ differentiable function.
 
 ```@example tutorial
 A = LagrangeInterpolation(u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Akima Interpolation
@@ -59,8 +56,7 @@ fit looks more natural.
 
 ```@example tutorial
 A = AkimaInterpolation(u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Constant Interpolation
@@ -71,16 +67,14 @@ passing the keyword argument `dir = :right`.
 
 ```@example tutorial
 A = ConstantInterpolation(u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 Or using the right endpoints:
 
 ```@example tutorial
 A = ConstantInterpolation(u, t, dir = :right)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Quadratic Spline
@@ -92,8 +86,7 @@ nearest to it.
 
 ```@example tutorial
 A = QuadraticSpline(u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Cubic Spline
@@ -103,8 +96,7 @@ which hits each of the data points exactly.
 
 ```@example tutorial
 A = CubicSpline(u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## B-Splines
@@ -118,8 +110,7 @@ uniformly spaced, we will use the `:ArcLen` and `:Average` choices:
 
 ```@example tutorial
 A = BSplineInterpolation(u, t, 3, :ArcLen, :Average)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 The approximating B-spline is a smoothed version of the B-spline. It again is
@@ -130,8 +121,7 @@ data. For example, if we use 4 control points, we get the result:
 
 ```@example tutorial
 A = BSplineApprox(u, t, 3, 4, :ArcLen, :Average)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Cubic Hermite Spline
@@ -141,8 +131,7 @@ This is the cubic (third order) Hermite interpolation. It matches the values and
 ```@example tutorial
 du = [-0.047, -0.058, 0.054, 0.012, -0.068, 0.0011]
 A = CubicHermiteSpline(du, u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## PCHIP Interpolation
@@ -163,8 +152,7 @@ This is the quintic (fifth order) Hermite interpolation. It matches the values a
 ddu = [0.0, -0.00033, 0.0051, -0.0067, 0.0029, 0.0]
 du = [-0.047, -0.058, 0.054, 0.012, -0.068, 0.0011]
 A = QuinticHermiteSpline(ddu, du, u, t)
-scatter(t, u, label = "input data")
-plot!(A)
+plot(A)
 ```
 
 ## Regularization Smoothing
@@ -258,8 +246,7 @@ match our data. Let's start with the guess of every `p` being zero, that is
 ```@example tutorial
 using Optim
 A = Curvefit(u, t, m, ones(4), LBFGS())
-scatter(t, u, label = "points", legend = :bottomright)
-plot!(A)
+plot(A)
 ```
 
 We can check what the fitted parameters are via:
@@ -275,8 +262,7 @@ is not good:
 
 ```@example tutorial
 A = Curvefit(u, t, m, zeros(4), LBFGS())
-scatter(t, u, label = "points", legend = :bottomright)
-plot!(A)
+plot(A)
 ```
 
 And the parameters show the issue: