Problem
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Given two 1d vectors, implement an iterator to return their elements alternately.
For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6]
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1, 3, 2, 4, 5, 6].
Follow up: What if you are given k 1d vectors? How well can your code be extended to such cases?
Clarification for the follow up question – Update (2015-09-18): The “Zigzag” order is not clearly defined and is ambiguous for k > 2 cases. If “Zigzag” does not look right to you, replace “Zigzag” with “Cyclic”. For example, given the following input:
[1,2,3] [4,5,6,7] [8,9] It should return [1,4,8,2,5,9,3,6,7].