Merge pull request youngyangyang04#1736 from Undertone0809/Undertone0…

…809-patch-1

Update 0242.有效的字母异位词.md

problems/0242.有效的字母异位词.md

@@ -123,12 +123,11 @@ Python：
 class Solution:
     def isAnagram(self, s: str, t: str) -> bool:
         record = [0] * 26
-        for i in range(len(s)):
+        for i in s:
             #并不需要记住字符a的ASCII，只要求出一个相对数值就可以了
-            record[ord(s[i]) - ord("a")] += 1
-        print(record)
-        for i in range(len(t)):
-            record[ord(t[i]) - ord("a")] -= 1
+            record[ord(i) - ord("a")] += 1
+        for i in t:
+            record[ord(i) - ord("a")] -= 1
         for i in range(26):
             if record[i] != 0:
                 #record数组如果有的元素不为零0，说明字符串s和t 一定是谁多了字符或者谁少了字符。