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1049.last-stone-weight-ii.java
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/*
* @lc app=leetcode id=1049 lang=java
*
* [1049] Last Stone Weight II
*
* https://leetcode.com/problems/last-stone-weight-ii/description/
*
* algorithms
* Medium (44.27%)
* Likes: 771
* Dislikes: 30
* Total Accepted: 20.3K
* Total Submissions: 45.8K
* Testcase Example: '[2,7,4,1,8,1]'
*
* We have a collection of rocks, each rock has a positive integer weight.
*
* Each turn, we choose any two rocks and smash them together. Suppose the
* stones have weights x and y with x <= y. The result of this smash is:
*
*
* If x == y, both stones are totally destroyed;
* If x != y, the stone of weight x is totally destroyed, and the stone of
* weight y has new weight y-x.
*
*
* At the end, there is at most 1 stone left. Return the smallest possible
* weight of this stone (the weight is 0 if there are no stones left.)
*
*
*
* Example 1:
*
*
* Input: [2,7,4,1,8,1]
* Output: 1
* Explanation:
* We can combine 2 and 4 to get 2 so the array converts to [2,7,1,8,1] then,
* we can combine 7 and 8 to get 1 so the array converts to [2,1,1,1] then,
* we can combine 2 and 1 to get 1 so the array converts to [1,1,1] then,
* we can combine 1 and 1 to get 0 so the array converts to [1] then that's the
* optimal value.
*
*
*
*
* Note:
*
*
* 1 <= stones.length <= 30
* 1 <= stones[i] <= 100
*
*/
// @lc code=start
import java.util.*;
class Solution {
public int lastStoneWeightII(int[] stones) {
int total = Arrays.stream(stones).sum();
HashMap<Integer,Integer> map = new HashMap<Integer,Integer>();
return minStone(stones,total,0,total,map);
}
int minStone(int arr[],int sum,int i,int total,HashMap<Integer,Integer> map){
if(i==arr.length){
return Math.abs((total-sum*2));
}
if(map.containsKey(sum)){
return map.get(sum);
}
int select = minStone(arr,sum - arr[i],i+1,total,map);
int notSelect = minStone(arr,sum,i+1,total,map);
int min = Math.min(select,notSelect);
map.put(sum,min);
return min;
}
}
// @lc code=end