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1345.jump-game-iv.java
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1345.jump-game-iv.java
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/*
* @lc app=leetcode id=1345 lang=java
*
* [1345] Jump Game IV
*
* https://leetcode.com/problems/jump-game-iv/description/
*
* algorithms
* Hard (39.77%)
* Likes: 301
* Dislikes: 21
* Total Accepted: 15K
* Total Submissions: 37.5K
* Testcase Example: '[100,-23,-23,404,100,23,23,23,3,404]'
*
* Given an array of integers arr, you are initially positioned at the first
* index of the array.
*
* In one step you can jump from index i to index:
*
*
* i + 1 where: i + 1 < arr.length.
* i - 1 where: i - 1 >= 0.
* j where: arr[i] == arr[j] and i != j.
*
*
* Return the minimum number of steps to reach the last index of the array.
*
* Notice that you can not jump outside of the array at any time.
*
*
* Example 1:
*
*
* Input: arr = [100,-23,-23,404,100,23,23,23,3,404]
* Output: 3
* Explanation: You need three jumps from index 0 --> 4 --> 3 --> 9. Note that
* index 9 is the last index of the array.
*
*
* Example 2:
*
*
* Input: arr = [7]
* Output: 0
* Explanation: Start index is the last index. You don't need to jump.
*
*
* Example 3:
*
*
* Input: arr = [7,6,9,6,9,6,9,7]
* Output: 1
* Explanation: You can jump directly from index 0 to index 7 which is last
* index of the array.
*
*
* Example 4:
*
*
* Input: arr = [6,1,9]
* Output: 2
*
*
* Example 5:
*
*
* Input: arr = [11,22,7,7,7,7,7,7,7,22,13]
* Output: 3
*
*
*
* Constraints:
*
*
* 1 <= arr.length <= 5 * 10^4
* -10^8 <= arr[i] <= 10^8
*
*
*/
// @lc code=start
class Solution {
public int minJumps(int[] arr) {
int n = arr.length;
Map<Integer,LinkedList<Integer>> map = new HashMap<>();
for(int i=0;i<arr.length;i++){
LinkedList<Integer> temp = map.get(arr[i]);
if(temp!=null){
temp.add(i);
map.put(arr[i],temp);
}
else{
temp = new LinkedList<>();
temp.add(i);
map.put(arr[i],temp);
}
}
Queue<Integer> queue = new LinkedList<Integer>();
queue.offer(0);
int steps = 0;
boolean[] visited = new boolean[n];
visited[0]=true;
while(!queue.isEmpty()){
int size = queue.size();
while(size-- >0){
int i = queue.poll();
if(i==n-1){
return steps;
}
List<Integer> next = map.get(arr[i]);
next.add(i-1);
next.add(i+1);
for(int j : next){
if(j>=0 && j<n && !visited[j]){
visited[j]=true;
queue.offer(j);
}
}
next.clear();
}
steps++;
}
return 0;
}
}
// @lc code=end