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200.number-of-islands.java
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200.number-of-islands.java
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/*
* @lc app=leetcode id=200 lang=java
*
* [200] Number of Islands
*
* https://leetcode.com/problems/number-of-islands/description/
*
* algorithms
* Medium (46.93%)
* Likes: 6701
* Dislikes: 217
* Total Accepted: 847.4K
* Total Submissions: 1.8M
* Testcase Example: '[["1","1","1","1","0"],["1","1","0","1","0"],["1","1","0","0","0"],["0","0","0","0","0"]]'
*
* Given an m x n 2d grid map of '1's (land) and '0's (water), return the
* number of islands.
*
* An island is surrounded by water and is formed by connecting adjacent lands
* horizontally or vertically. You may assume all four edges of the grid are
* all surrounded by water.
*
*
* Example 1:
*
*
* Input: grid = [
* ["1","1","1","1","0"],
* ["1","1","0","1","0"],
* ["1","1","0","0","0"],
* ["0","0","0","0","0"]
* ]
* Output: 1
*
*
* Example 2:
*
*
* Input: grid = [
* ["1","1","0","0","0"],
* ["1","1","0","0","0"],
* ["0","0","1","0","0"],
* ["0","0","0","1","1"]
* ]
* Output: 3
*
*
*
* Constraints:
*
*
* m == grid.length
* n == grid[i].length
* 1 <= m, n <= 300
* grid[i][j] is '0' or '1'.
*
*
*/
// @lc code=start
class Solution {
public int numIslands(char[][] grid) {
int n = grid.length;
int m = grid[0].length;
if(n==0){
return 0;
}
int count = 0;
for(int i=0;i<n;i++){
for(int j=0;j<m;j++){
if(grid[i][j]=='1'){
dfs(grid,i,j);
++count;
}
}
}
return count;
}
void dfs(char[][] grid,int i,int j){
if(i<0 || i>=grid.length || j<0 || j>=grid[0].length || grid[i][j]!='1'){
return;
}
grid[i][j]='0';
dfs(grid,i+1,j);
dfs(grid,i-1,j);
dfs(grid,i,j+1);
dfs(grid,i,j-1);
}
}
// @lc code=end