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279.perfect-squares.java
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279.perfect-squares.java
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/*
* @lc app=leetcode id=279 lang=java
*
* [279] Perfect Squares
*
* https://leetcode.com/problems/perfect-squares/description/
*
* algorithms
* Medium (47.49%)
* Likes: 3243
* Dislikes: 196
* Total Accepted: 326.7K
* Total Submissions: 687.2K
* Testcase Example: '12'
*
* Given a positive integer n, find the least number of perfect square numbers
* (for example, 1, 4, 9, 16, ...) which sum to n.
*
* Example 1:
*
*
* Input: n = 12
* Output: 3
* Explanation: 12 = 4 + 4 + 4.
*
* Example 2:
*
*
* Input: n = 13
* Output: 2
* Explanation: 13 = 4 + 9.
*/
// @lc code=start
import java.util.*;
class Solution {
public int numSquares(int n) {
// Map<Integer, Integer> map = new HashMap<Integer, Integer>();
// return perfectSquare(n,map);
return perfectSquare(n);
}
static int perfectSquare(int n) {
if(n < 4) return n;
int dp[] = new int[n + 1];
Arrays.fill(dp, Integer.MAX_VALUE);
dp[0] = 0;
dp[1] = 1;
dp[2] = 2;
dp[3] = 3;
for (int i = 4; i <= n; i++) {
for (int j = 1; j * j <= i; j++) {
dp[i] = Math.min(dp[i], dp[i - j * j] + 1);
}
}
return dp[n];
}
static int perfectSquare(int n, Map<Integer, Integer> map) {
if (map.containsKey(n)) {
return map.get(n);
}
if (n < 4) {
return n;
}
int ways = n;
for (int i = 1; i * i <= n; i++) {
int amount = n - i * i;
ways = Math.min(ways, perfectSquare(amount, map) + 1);
}
map.put(n, ways);
return ways;
}
}
// @lc code=end