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394.decode-string.java
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394.decode-string.java
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/*
* @lc app=leetcode id=394 lang=java
*
* [394] Decode String
*
* https://leetcode.com/problems/decode-string/description/
*
* algorithms
* Medium (50.18%)
* Likes: 3506
* Dislikes: 177
* Total Accepted: 227.7K
* Total Submissions: 452.6K
* Testcase Example: '"3[a]2[bc]"'
*
* Given an encoded string, return its decoded string.
*
* The encoding rule is: k[encoded_string], where the encoded_string inside the
* square brackets is being repeated exactly k times. Note that k is guaranteed
* to be a positive integer.
*
* You may assume that the input string is always valid; No extra white spaces,
* square brackets are well-formed, etc.
*
* Furthermore, you may assume that the original data does not contain any
* digits and that digits are only for those repeat numbers, k. For example,
* there won't be input like 3a or 2[4].
*
*
* Example 1:
* Input: s = "3[a]2[bc]"
* Output: "aaabcbc"
* Example 2:
* Input: s = "3[a2[c]]"
* Output: "accaccacc"
* Example 3:
* Input: s = "2[abc]3[cd]ef"
* Output: "abcabccdcdcdef"
* Example 4:
* Input: s = "abc3[cd]xyz"
* Output: "abccdcdcdxyz"
*
*/
// @lc code=start
class Solution {
int i=0;
public String decodeString(String s) {
StringBuilder sb = new StringBuilder("");
int count = 0;
String temp_string = "";
while(i<s.length()){
char ch = s.charAt(i);
i++;
if(ch=='['){
temp_string = decodeString(s);
for(int j=0;j<count;j++){
sb.append(temp_string);
}
count=0;
}
else if(ch ==']'){
break;
}
else if(Character.isAlphabetic(ch)){
sb.append(ch);
}
else{
count = count*10 +ch -'0';
}
}
return sb.toString();
}
}
// @lc code=end