指令顺序重排项目进展

[GoogleCodeExporter]

基本思路，通过改造d2j-jarjasmin,按新的顺序生成.j文件，然后�
��d2j-jasmin2jar编译，新生成的.jar文件能让jd-gui正确反编译。
把代码划分为顺序代码C，判断代码P,分支代码S，goto代码G,标�
��代码L等，然后组装到有向图中，然后通过找环，识别各类��
�环，判断，形成新的代码执行顺序，生成.j文件。
目前进展，复合的循环基本解决，但try比较难。
如代码修改前反编译为
  public static void checkPath(String paramString1, String paramString2, String paramString3)
  {
    if (paramString2 == null);
    String[] arrayOfString;
    do
    {
      return;
      arrayOfString = paramString2.split(paramString3);
    }
    while (arrayOfString == null);
    Object localObject = null;
    for (int i = 0; ; ++i)
    {
      if (i < arrayOfString.length);
      label40: if (!arrayOfString[i].equals(""))
        break;
    }
    if (localObject != null);
    for (localObject = localObject + FILE + arrayOfString[i]; ; localObject = FILE + arrayOfString[i])
    {
      File localFile = new File(paramString1 + (String)localObject);
      if (!localFile.exists());
      localFile.mkdir();
      break label40:
    }
  }
修改后可以为：
  public static void checkPath(String paramString1, String paramString2, String paramString3)
  {
    if (paramString2 == null)
      return;
    String[] arrayOfString = paramString2.split(paramString3);
    if (arrayOfString == null)
      return;
    Object localObject = null;
    for (int i = 0; i < arrayOfString.length; ++i)
    {
      if ((!arrayOfString[i].equals("")) || (localObject != null))
        localObject = localObject + FILE + arrayOfString[i];
      else
        localObject = FILE + arrayOfString[i];
      File localFile = new File(paramString1 + (String)localObject);
      if (localFile.exists())
        continue;
      localFile.mkdir();
    }
  }
错误明显减少。

Original issue reported on code.google.com by [email protected] on 28 Oct 2013 at 3:57

[GoogleCodeExporter]

[deleted comment]

[GoogleCodeExporter]

try-catch 比较难，会被分割，特别是 try-finally 识别有困难

Original comment by [email protected] on 5 Nov 2013 at 9:00