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@zvonimir : This is really a SMACK question and should have been posted on the SMACK (if it has one). But please provide some answer here to help out @Luweicai . |
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The loop invariant
invariant xxx
will be transferred into the form ofassert XXX
in the smack-generated boogie code (from c code). I wonder the form of free loop invariantfree invariant XXX
in the smack-generated boogie code.Beta Was this translation helpful? Give feedback.
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