How to specify a route in urls in django 3?

[mrkaban]

The manual says "url (r '^ list $', views.product_list)", but this is for the old version of django.
How to register this route in Django 3?

[mrkaban]

Maybe I am doing something wrong? Doesn't filter data, this is what I have:

urls.py

urlpatterns =[
re_path(r'^language$', product_list),
path('category/<str:slug>/', SoftsByCategory.as_view(), name='category'),

filters.py

class SoftFilter(django_filters.FilterSet):
    STATUS_CHOICES = (
        ('English', 'English'),
        ('Russian', 'Russian'),
    )

    language = django_filters.ChoiceFilter(field_name='language', choices=STATUS_CHOICES)

    class Meta:
        model = Soft
        fields = {'language'}

views.py

class SoftsByCategory(ListView):
    template_name = 'blog.html'
    context_object_name = 'softs'
    paginate_by = 9
    allow_empty = False
    #require_http_methods = ['GET', 'HEAD']

    def get_queryset(self):
        return Soft.objects.filter(category__slug=self.kwargs['slug'], is_published=True)

    def get_context_data(self, *, object_list=None, **kwargs):
        context = super().get_context_data(**kwargs)
        context['title'] = Category.objects.get(slug=self.kwargs['slug'])
        return context

def product_list(request):
    f = SoftFilter(request.GET, queryset=Soft.objects.filter())
    return render(request, 'blog.html', {'filter': f})`

[carltongibson]

You really need to try a support forum I'm afraid. Good luck

[mrkaban]

and where he? the saddest thing is that the manual contains NOT UP-TO-DATE information

[mrkaban]

I understood, thanks for "helping". I will implement without this "wonderful" plugin.

[carltongibson]

Ah, OK the docs were using the old url() — You need to use path or re_path as per the Django URL dispatcher docs.

Fixed in #1339.