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Q15_graph_coloring.cpp
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// There is an undirected graph with n nodes, where each node is numbered between 0 and n - 1. You are given a 2D array graph, where graph[u] is an array of nodes that node u is adjacent to. More formally, for each v in graph[u], there is an undirected edge between node u and node v. The graph has the following properties:
// There are no self-edges (graph[u] does not contain u).
// There are no parallel edges (graph[u] does not contain duplicate values).
// If v is in graph[u], then u is in graph[v] (the graph is undirected).
// The graph may not be connected, meaning there may be two nodes u and v such that there is no path between them.
// A graph is bipartite if the nodes can be partitioned into two independent sets A and B such that every edge in the graph connects a node in set A and a node in set B.
// Return true if and only if it is bipartite.
// Example 1:
// Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]
// Output: false
// Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.
// Example 2:
// Input: graph = [[1,3],[0,2],[1,3],[0,2]]
// Output: true
// Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.
#include<bits/stdc++.h>
using namespace std;
class Solution {
private:
bool dfs(vector<vector<int>>& graph, int src, vector<int>& colors) {
if(colors[src] == -1) colors[src] = 1;
for(int &v : graph[src]) {
if(colors[v] == -1) {
colors[v] = !colors[src];
if(!dfs(graph, v, colors)) return false;
}
else if(colors[v] == colors[src]) return false;
}
return true;
}
public:
bool isBipartite(vector<vector<int>>& graph) {
int n = graph.size();
vector<int> colors(n, -1);
for(int i=0; i<n; i++) {
if(colors[i] == -1)
if(!dfs(graph, i, colors)) return false;
}
return true;
}
};
// Time Complexity : O(n)
// Space Complexity : O(n)