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English Version

题目描述

给你一个字符串 s 、一个字符串 t 。返回 s 中涵盖 t 所有字符的最小子串。如果 s 中不存在涵盖 t 所有字符的子串,则返回空字符串 ""

注意:如果 s 中存在这样的子串,我们保证它是唯一的答案。

 

示例 1:

输入:s = "ADOBECODEBANC", t = "ABC"
输出:"BANC"

示例 2:

输入:s = "a", t = "a"
输出:"a"

 

提示:

  • 1 <= s.length, t.length <= 105
  • st 由英文字母组成

 

进阶:你能设计一个在 o(n) 时间内解决此问题的算法吗?

解法

滑动窗口

Python3

Java

TypeScript

function minWindow(s: string, t: string): string {
    let n1 = s.length,
        n2 = t.length;
    if (n1 < n2) return "";
    let need = new Array(128).fill(0);
    let window = new Array(128).fill(0);
    for (let i = 0; i < n2; ++i) {
        ++need[t.charCodeAt(i)];
    }

    let left = 0,
        right = 0;
    let res = "";
    let count = 0;
    let min = n1 + 1;
    while (right < n1) {
        let cur = s.charCodeAt(right);
        ++window[cur];
        if (need[cur] > 0 && need[cur] >= window[cur]) {
            ++count;
        }
        while (count == n2) {
            cur = s.charCodeAt(left);
            if (need[cur] > 0 && need[cur] >= window[cur]) {
                --count;
            }
            if (right - left + 1 < min) {
                min = right - left + 1;
                res = s.slice(left, right + 1);
            }
            --window[cur];
            ++left;
        }
        ++right;
    }
    return res;
}

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