There are a total of n
courses you have to take, labeled from 0
to n-1
.
Some courses may have direct prerequisites, for example, to take course 0 you have first to take course 1, which is expressed as a pair: [1,0]
Given the total number of courses n
, a list of direct prerequisite
pairs and a list of queries
pairs.
You should answer for each queries[i]
whether the course queries[i][0]
is a prerequisite of the course queries[i][1]
or not.
Return a list of boolean, the answers to the given queries
.
Please note that if course a is a prerequisite of course b and course b is a prerequisite of course c, then, course a is a prerequisite of course c.
Example 1:
Input: n = 2, prerequisites = [[1,0]], queries = [[0,1],[1,0]] Output: [false,true] Explanation: course 0 is not a prerequisite of course 1 but the opposite is true.
Example 2:
Input: n = 2, prerequisites = [], queries = [[1,0],[0,1]] Output: [false,false] Explanation: There are no prerequisites and each course is independent.
Example 3:
Input: n = 3, prerequisites = [[1,2],[1,0],[2,0]], queries = [[1,0],[1,2]] Output: [true,true]
Example 4:
Input: n = 3, prerequisites = [[1,0],[2,0]], queries = [[0,1],[2,0]] Output: [false,true]
Example 5:
Input: n = 5, prerequisites = [[0,1],[1,2],[2,3],[3,4]], queries = [[0,4],[4,0],[1,3],[3,0]] Output: [true,false,true,false]
Constraints:
2 <= n <= 100
0 <= prerequisite.length <= (n * (n - 1) / 2)
0 <= prerequisite[i][0], prerequisite[i][1] < n
prerequisite[i][0] != prerequisite[i][1]
- The prerequisites graph has no cycles.
- The prerequisites graph has no repeated edges.
1 <= queries.length <= 10^4
queries[i][0] != queries[i][1]
DFS.
class Solution:
def checkIfPrerequisite(self, numCourses: int, prerequisites: List[List[int]], queries: List[List[int]]) -> List[bool]:
@lru_cache(None)
def dfs(a, b):
if b in g[a] or a == b:
return True
for c in g[a]:
if dfs(c, b):
return True
return False
g = defaultdict(set)
for a, b in prerequisites:
g[a].add(b)
return [dfs(a, b) for a, b in queries]
class Solution {
public List<Boolean> checkIfPrerequisite(int numCourses, int[][] prerequisites, int[][] queries) {
int[][] g = new int[numCourses][numCourses];
for (int i = 0; i < numCourses; ++i) {
Arrays.fill(g[i], -1);
}
for (int[] e : prerequisites) {
int a = e[0], b = e[1];
g[a][b] = 1;
}
List<Boolean> ans = new ArrayList<>();
for (int[] e : queries) {
int a = e[0], b = e[1];
ans.add(dfs(a, b, g));
}
return ans;
}
private boolean dfs(int a, int b, int[][] g) {
if (g[a][b] != -1) {
return g[a][b] == 1;
}
if (a == b) {
g[a][b] = 1;
return true;
}
for (int i = 0; i < g[a].length; ++i) {
if (g[a][i] == 1 && dfs(i, b, g)) {
g[a][b] = 1;
return true;
}
}
g[a][b] = 0;
return false;
}
}
class Solution {
public:
vector<bool> checkIfPrerequisite(int numCourses, vector<vector<int>>& prerequisites, vector<vector<int>>& queries) {
vector<vector<int>> g(numCourses, vector<int>(numCourses, -1));
for (auto& e : prerequisites)
{
int a = e[0], b = e[1];
g[a][b] = 1;
}
vector<bool> ans;
for (auto& e : queries)
{
int a = e[0], b = e[1];
ans.push_back(dfs(a, b, g));
}
return ans;
}
bool dfs(int a, int b, vector<vector<int>>& g) {
if (g[a][b] != -1) return g[a][b] == 1;
if (a == b)
{
g[a][b] = 1;
return true;
}
for (int i = 0; i < g[a].size(); ++i)
{
if (g[a][i] == 1 && dfs(i, b, g))
{
g[a][b] = 1;
return true;
}
}
g[a][b] = 0;
return false;
}
};
func checkIfPrerequisite(numCourses int, prerequisites [][]int, queries [][]int) []bool {
g := make([][]int, numCourses)
for i := range g {
g[i] = make([]int, numCourses)
for j := range g[i] {
g[i][j] = -1
}
}
for _, e := range prerequisites {
a, b := e[0], e[1]
g[a][b] = 1
}
var ans []bool
var dfs func(a, b int) bool
dfs = func(a, b int) bool {
if g[a][b] != -1 {
return g[a][b] == 1
}
if a == b {
g[a][b] = 1
return true
}
for i, c := range g[a] {
if c == 1 && dfs(i, b) {
g[a][b] = 1
return true
}
}
g[a][b] = 0
return false
}
for _, e := range queries {
a, b := e[0], e[1]
ans = append(ans, dfs(a, b))
}
return ans
}