README_EN.md

1672. Richest Customer Wealth

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Description

You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has.

A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.

 

Example 1:

Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.

Example 2:

Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation: 
1st customer has wealth = 6
2nd customer has wealth = 10 
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.

Example 3:

Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17

 

Constraints:

• m == accounts.length
• n == accounts[i].length
• 1 <= m, n <= 50
• 1 <= accounts[i][j] <= 100

Solutions

Python3

class Solution:
    def maximumWealth(self, accounts: List[List[int]]) -> int:
        return max(sum(account) for account in accounts)

Java

class Solution {
    public int maximumWealth(int[][] accounts) {
        int res = 0;
        for (int[] account : accounts) {
            int t = 0;
            for (int money : account) {
                t += money;
            }
            res = Math.max(res, t);
        }
        return res;
    }
}

C++

class Solution {
public:
    int maximumWealth(vector<vector<int>>& accounts) {
        int res = 0;
        for (auto& account : accounts)
            res = max(res, accumulate(account.begin(), account.end(), 0));
        return res;
    }
};

Go

func maximumWealth(accounts [][]int) int {
	res := 0
	for _, account := range accounts {
		t := 0
		for _, money := range account {
			t += money
		}
		if t > res {
			res = t
		}
	}
	return res
}

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