README_EN.md

1721. Swapping Nodes in a Linked List

中文文档

Description

You are given the head of a linked list, and an integer k.

Return the head of the linked list after swapping the values of the kth node from the beginning and the kth node from the end (the list is 1-indexed).

 

Example 1:

Input: head = [1,2,3,4,5], k = 2
Output: [1,4,3,2,5]

Example 2:

Input: head = [7,9,6,6,7,8,3,0,9,5], k = 5
Output: [7,9,6,6,8,7,3,0,9,5]

Example 3:

Input: head = [1], k = 1
Output: [1]

Example 4:

Input: head = [1,2], k = 1
Output: [2,1]

Example 5:

Input: head = [1,2,3], k = 2
Output: [1,2,3]

 

Constraints:

• The number of nodes in the list is n.
• 1 <= k <= n <= 105
• 0 <= Node.val <= 100

Solutions

Python3

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def swapNodes(self, head: ListNode, k: int) -> ListNode:
        fast = head
        for _ in range(k - 1):
            fast = fast.next
        p = fast
        slow = head
        while fast.next:
            slow, fast = slow.next, fast.next
        q = slow
        p.val, q.val = q.val, p.val
        return head

Java

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public ListNode swapNodes(ListNode head, int k) {
        ListNode fast = head;
        while (--k > 0) {
            fast = fast.next;
        }
        ListNode p = fast;
        ListNode slow = head;
        while (fast.next != null) {
            slow = slow.next;
            fast = fast.next;
        }
        ListNode q = slow;
        int t = p.val;
        p.val = q.val;
        q.val = t;
        return head;
    }
}

...