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题目描述

给你一个 数字 字符串数组 nums 和一个 数字 字符串 target ,请你返回 nums[i] + nums[j] (两个字符串连接)结果等于 target 的下标 (i, j) (需满足 i != j)的数目。

 

示例 1:

输入:nums = ["777","7","77","77"], target = "7777"
输出:4
解释:符合要求的下标对包括:
- (0, 1):"777" + "7"
- (1, 0):"7" + "777"
- (2, 3):"77" + "77"
- (3, 2):"77" + "77"

示例 2:

输入:nums = ["123","4","12","34"], target = "1234"
输出:2
解释:符合要求的下标对包括
- (0, 1):"123" + "4"
- (2, 3):"12" + "34"

示例 3:

输入:nums = ["1","1","1"], target = "11"
输出:6
解释:符合要求的下标对包括
- (0, 1):"1" + "1"
- (1, 0):"1" + "1"
- (0, 2):"1" + "1"
- (2, 0):"1" + "1"
- (1, 2):"1" + "1"
- (2, 1):"1" + "1"

 

提示:

  • 2 <= nums.length <= 100
  • 1 <= nums[i].length <= 100
  • 2 <= target.length <= 100
  • nums[i] 和 target 只包含数字。
  • nums[i] 和 target 不含有任何前导 0 。

解法

Python3

Java

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