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0040.go
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// Source: https://leetcode.com/problems/combination-sum-ii
// Title: Combination Sum II
// Difficulty: Medium
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sum to target.
//
// Each number in candidates may only be used once in the combination.
//
// Note: The solution set must not contain duplicate combinations.
//
// Example 1:
//
// Input: candidates = [10,1,2,7,6,1,5], target = 8
// Output:
// [
// [1,1,6],
// [1,2,5],
// [1,7],
// [2,6]
// ]
//
// Example 2:
//
// Input: candidates = [2,5,2,1,2], target = 5
// Output:
// [
// [1,2,2],
// [5]
// ]
//
// Constraints:
//
// 1 <= candidates.length <= 100
// 1 <= candidates[i] <= 50
// 1 <= target <= 30
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
package main
func combinationSum2(candidates []int, target int) [][]int {
candidateMap := make(map[int]int, len(candidates)) // map candidate to its numbers
for _, num := range candidates {
candidateMap[num]++
}
nums := make([]int, 0, len(candidateMap))
counts := make([]int, 0, len(candidateMap))
for num, count := range candidateMap {
nums = append(nums, num)
counts = append(counts, count)
}
res := make([][]int, 0)
_combinationSum2(nums, counts, 0, target, &res)
return res
}
func _combinationSum2(nums, counts []int, idx int, target int, res *[][]int, solution ...int) {
if target < 0 {
return
}
if target == 0 {
*res = append(*res, append([]int{}, solution...))
return
}
solution = append(solution, 0)
for i := idx; i < len(nums); i++ {
count := counts[i]
if count == 0 {
continue
}
num := nums[i]
solution[len(solution)-1] = num
counts[i]--
_combinationSum2(nums, counts, i, target-num, res, solution...)
counts[i]++
}
}