-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path0045.go
63 lines (57 loc) · 1.49 KB
/
0045.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
// Source: https://leetcode.com/problems/jump-game-ii
// Title: Jump Game II
// Difficulty: Hard
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given an array of non-negative integers nums, you are initially positioned at the first index of the array.
//
// Each element in the array represents your maximum jump length at that position.
//
// Your goal is to reach the last index in the minimum number of jumps.
//
// You can assume that you can always reach the last index.
//
// Example 1:
//
// Input: nums = [2,3,1,1,4]
// Output: 2
// Explanation: The minimum number of jumps to reach the last index is 2. Jump 1 step from index 0 to 1, then 3 steps to the last index.
//
// Example 2:
//
// Input: nums = [2,3,0,1,4]
// Output: 2
//
// Constraints:
//
// 1 <= nums.length <= 10^4
// 0 <= nums[i] <= 1000
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
package main
func jump1(nums []int) int {
target := len(nums) - 1
if target == 0 {
return 0
}
step := 0
currMax := 0 // max reachable index
prevMax := 0 // max reachable index in (step-1) steps
for i, num := range nums {
currMax = _max(currMax, i+num)
if i == prevMax {
step++
prevMax = currMax
if currMax >= target {
break
}
}
}
return step
}
func _max(a, b int) int {
if a > b {
return a
}
return b
}