-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path0118.go
45 lines (40 loc) · 1.18 KB
/
0118.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
// Source: https://leetcode.com/problems/pascals-triangle
// Title: Pascal's Triangle
// Difficulty: Easy
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given an integer numRows, return the first numRows of Pascal's triangle.
//
// In Pascal's triangle, each number is the sum of the two numbers directly above it as shown:
//
// https://upload.wikimedia.org/wikipedia/commons/0/0d/PascalTriangleAnimated2.gif
//
// Example 1:
//
// Input: numRows = 5
// Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]
//
// Example 2:
//
// Input: numRows = 1
// Output: [[1]]
//
// Constraints:
//
// 1 <= numRows <= 30
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
package main
func generate(numRows int) [][]int {
triangle := make([][]int, numRows)
triangle[0] = []int{1}
for i := 1; i < numRows; i++ {
triangle[i] = make([]int, i+1)
triangle[i][0] = 1
for j := 1; j < i; j++ {
triangle[i][j] = triangle[i-1][j] + triangle[i-1][j-1]
}
triangle[i][i] = 1
}
return triangle
}