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Why is it not feasible in general for function types to be instances of the Eq class? #3

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derekmahar opened this issue Oct 11, 2019 · 0 comments

derekmahar commented Oct 11, 2019

The solution does not explain why it is not feasible in general for function types to be instances of the Eq class.

programming-in-haskell/03-types-and-classes/03.11-exercises.hs

Line 58 in 0af2c48

-- It is not feasible in general to compare two functions for equality.

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