diff --git a/Manuals/SMV_Technical_Reference_Guide/SMV_Technical_Reference_Guide.tex b/Manuals/SMV_Technical_Reference_Guide/SMV_Technical_Reference_Guide.tex
index 07a0bba43f..fcce1515c7 100644
--- a/Manuals/SMV_Technical_Reference_Guide/SMV_Technical_Reference_Guide.tex
+++ b/Manuals/SMV_Technical_Reference_Guide/SMV_Technical_Reference_Guide.tex
@@ -1694,7 +1694,7 @@ \subsection{FED example}
 &= &\mathrm{FED}_\mathrm{CO}(t)\times\mathrm{HV}_\mathrm{CO_2}(t)+\mathrm{FED}_\mathrm{O_2}(t)\\
 \nonumber
  &= &\left(2.764 \times 10^{-5} \, \mathrm{CO}^{1.036}\times
-\frac{ \exp( 0.1903 \, \mathrm{CO_2} +  2.0004 ) }{7.1}\exp( -8.13
+\frac{ \exp( 0.1903 \, \mathrm{CO_2} +  2.0004 ) }{7.1} + \exp( -8.13
 + 0.54 \, (20.9 - \mathrm{O_2}) )\right) t\\
 \end{eqnarray}
 
@@ -1702,8 +1702,8 @@ \subsection{FED example}
 $\mathrm{CO_2}$ and $\mathrm{O_2}$ are constant.
 The first for a smoke filled room with CO=\SI{10000}{ppm},
 $\mathrm{CO_2}=5 \%$ and $\mathrm{O_2}=10 \%$ and the second for a
-room with ambient conditions with CO=\SI{9}{ppm},
-$\mathrm{CO_2}=0 \%$ and $\mathrm{O_2}=21 \%$
+room with ambient conditions with CO=\SI{0}{ppm},
+$\mathrm{CO_2}=9 \%$ and $\mathrm{O_2}=21 \%$
 
 \begin{figure}[bph]
 \begin{center}