class Solution { public int findKthLargest(int[] nums, int k) { int[] temp = new int[nums.length]; sort(nums, 0, nums.length - 1, temp); return nums[nums.length - k]; }
private static void sort(int[] arr, int left, int right, int[] temp) {
if (left < right) {
int mid = (left + right) / 2;
sort(arr, left, mid, temp);//左边归并排序,使得左子序列有序
sort(arr, mid + 1, right, temp);//右边归并排序,使得右子序列有序
merge(arr, left, mid, right, temp);//将两个有序子数组合并操作
}
}
private static void merge(int[] arr, int left, int mid, int right, int[] temp) {
int i = left;
int j = mid + 1;
int t = 0;
while (i <= mid && j <= right) {
if (arr[i] <= arr[j]) {
temp[t++] = arr[i++];
} else {
temp[t++] = arr[j++];
}
}
while (i <= mid) {//将左边剩余元素填充进temp中
temp[t++] = arr[i++];
}
while (j <= right) {//将右序列剩余元素填充进temp中
temp[t++] = arr[j++];
}
t = 0;
//将temp中的元素全部拷贝到原数组中
while (left <= right) {
arr[left++] = temp[t++];
}
}
}