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main2.cpp
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/// Source : https://leetcode.com/problems/coloring-a-border/
/// Author : liuyubobobo
/// Time : 2019-04-30
#include <iostream>
#include <vector>
#include <set>
using namespace std;
/// DFS - Check border directly during DFS
/// Time Complexity: O(m * n)
/// Space Complexity: O(m * n)
class Solution {
private:
const int d[4][2] = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
int m, n;
public:
vector<vector<int>> colorBorder(vector<vector<int>>& grid, int r0, int c0, int color) {
m = grid.size();
n = grid[0].size();
int target = grid[r0][c0];
if(target == color) return grid;
vector<pair<int, int>> border;
set<pair<int, int>> visited;
dfs(grid, r0, c0, target, border, visited);
for(const pair<int, int>& p: border)
grid[p.first][p.second] = color;
return grid;
}
private:
void dfs(vector<vector<int>>& grid, int x, int y, int target,
vector<pair<int, int>>& border, set<pair<int, int>>& visited){
visited.insert(make_pair(x, y));
int around = 0;
for(int i = 0; i < 4; i ++){
int nextx = x + d[i][0], nexty = y + d[i][1];
if(nextx >= 0 && nextx < m && nexty >= 0 && nexty < n && grid[nextx][nexty] == target){
around ++;
if(!visited.count(make_pair(nextx, nexty)))
dfs(grid, nextx, nexty, target, border, visited);
}
}
if(around != 4) border.push_back(make_pair(x, y));
}
};
void print_2dvec(const vector<vector<int>>& vec){
for(const vector<int>& row: vec){
for(int e: row) cout << e << " "; cout << endl;
}
}
int main() {
vector<vector<int>> grid1 = {{1,2,1},{1,2,2},{2,2,1}};
vector<vector<int>> res1 = Solution().colorBorder(grid1, 1, 1, 2);
print_2dvec(res1);
// 1 2 1
// 1 2 2
// 2 2 1
vector<vector<int>> grid2 = {{1,2,1,2,1,2},{2,2,2,2,1,2},{1,2,2,2,1,2}};
vector<vector<int>> res2 = Solution().colorBorder(grid2, 1, 3, 1);
print_2dvec(res2);
// 1 1 1 1 1 2
// 1 2 1 1 1 2
// 1 1 1 1 1 2
return 0;
}