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For examples like the following, removing the semi-colon will make the example parse.
let y = 'a'.ToString(); do ()
The presence of ';' prevents the scanner from inserting a dedent token required to close the declaration expression.
';'
dedent
Expected result:
should parse the same as:
let y = 'a'.ToString() do ()
The text was updated successfully, but these errors were encountered:
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For examples like the following, removing the semi-colon will make the example parse.
The presence of
';'
prevents the scanner from inserting adedent
token required to close the declaration expression.Expected result:
should parse the same as:
The text was updated successfully, but these errors were encountered: