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Results of Code LLama 34B on HumanEval/146

Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

def specialFilter(nums):
    """Write a function that takes an array of numbers as input and returns 
    the number of elements in the array that are greater than 10 and both 
    first and last digits of a number are odd (1, 3, 5, 7, 9).
    For example:
    specialFilter([15, -73, 14, -15]) => 1 
    specialFilter([33, -2, -3, 45, 21, 109]) => 2
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def specialFilter(nums):
    """Write a function that takes an array of numbers as input and returns 
    the number of elements in the array that are greater than 10 and both 
    first and last digits of a number are odd (1, 3, 5, 7, 9).
    For example:
    specialFilter([15, -73, 14, -15]) => 1 
    specialFilter([33, -2, -3, 45, 21, 109]) => 2
    """count = 0
    for num in nums:
        if num > 10:
            odd_digits = (1, 3, 5, 7, 9)
            number_as_string = str(num)
            if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:
                count += 1
        
    return count

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate([5, -2, 1, -5]) == 0  
    assert candidate([15, -73, 14, -15]) == 1
    assert candidate([33, -2, -3, 45, 21, 109]) == 2
    assert candidate([43, -12, 93, 125, 121, 109]) == 4
    assert candidate([71, -2, -33, 75, 21, 19]) == 3


    # Check some edge cases that are easy to work out by hand.
    assert candidate([1]) == 0              
    assert candidate([]) == 0

Runs

❌ Run 1

Start time: 2023-09-01 02:46:12
Duration: 4.27s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 in [1, 3, 5, 7, 9] and num // 10 in [1, 3, 5, 7, 9]:
            count += 1
    return count

❌ Run 2

Start time: 2023-09-01 02:49:10
Duration: 5.52s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 in [1, 3, 5, 7, 9] and num // 10 in [1, 3, 5, 7, 9]:
            count += 1
    return count

❌ Run 3

Start time: 2023-09-01 02:52:04
Duration: 3.43s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 & 1 == 1 and num // 10 & 1 == 1:
            count += 1
    return count

❌ Run 4

Start time: 2023-09-01 02:54:56
Duration: 3.72s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 & 1 and num // 10 & 1:
            count += 1
    return count

❌ Run 5

Start time: 2023-09-01 02:57:59
Duration: 4.28s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 & 1 == 1 and num // 10 & 1 == 1:
            count += 1
    return count

❌ Run 6

Start time: 2023-09-01 03:01:03
Duration: 5.11s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 in [1, 3, 5, 7, 9] and num // 10 in [1, 3, 5, 7, 9]:
            count += 1
    return count

❌ Run 7

Start time: 2023-09-01 03:04:01
Duration: 4.23s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 & 1 and num // 10 & 1:
            count += 1
    return count

❌ Run 8

Start time: 2023-09-01 03:07:04
Duration: 4.76s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 in [1, 3, 5, 7, 9] and num // 10 in [1, 3, 5, 7, 9]:
            count += 1
    return count

❌ Run 9

Start time: 2023-09-01 03:10:07
Duration: 4.1s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 & 1 and num // 10 & 1:
            count += 1
    return count

❌ Run 10

Start time: 2023-09-01 03:13:05
Duration: 3.57s
Result: Fail

def specialFilter(nums):
    count = 0
    for num in nums:
        if num > 10 and num % 10 & 1 == 1 and num // 10 & 1 == 1:
            count += 1
    return count