147.md

Results of Code LLama 34B on HumanEval/147

Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """A = [i*i - i + 1 for i in range(1,n+1)]
    ans = []
    for i in range(n):
        for j in range(i+1,n):
            for k in range(j+1,n):
                if (A[i]+A[j]+A[k])%3 == 0:
                    ans += [(A[i],A[j],A[k])]
    return len(ans)

Unit tests

def check(candidate):

    assert candidate(5) == 1
    assert candidate(6) == 4
    assert candidate(10) == 36
    assert candidate(100) == 53361

Runs

❌ Run 1

Start time: 2023-09-01 02:46:10
Duration: 5.62s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 2

Start time: 2023-09-01 02:49:09
Duration: 12.56s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(len(a)):
        for j in range(i + 1, len(a)):
            for k in range(j + 1, len(a)):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 3

Start time: 2023-09-01 02:52:03
Duration: 5.34s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 4

Start time: 2023-09-01 02:54:56
Duration: 12.88s
Result: Fail

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(len(a)):
        for j in range(i + 1, len(a)):
            for k in range(j + 1, len(a)):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 5

Start time: 2023-09-01 02:57:58
Duration: 6.47s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 6

Start time: 2023-09-01 03:01:02
Duration: 14.13s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 7

Start time: 2023-09-01 03:03:59
Duration: 6.36s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(len(a)):
        for j in range(i + 1, len(a)):
            for k in range(j + 1, len(a)):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 8

Start time: 2023-09-01 03:07:02
Duration: 8.86s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(len(a)):
        for j in range(i + 1, len(a)):
            for k in range(j + 1, len(a)):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 9

Start time: 2023-09-01 03:10:04
Duration: 6.34s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(len(a)):
        for j in range(i + 1, len(a)):
            for k in range(j + 1, len(a)):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count

❌ Run 10

Start time: 2023-09-01 03:13:04
Duration: 5.92s
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if a[i] + a[j] + a[k] % 3 == 0:
                    count += 1
    return count