115.md

Results of GPT-3.5 on HumanEval/115

Date: 18 July, 2023
Model: gpt-3.5-turbo
Temperature: 0.2
Passing runs: 2
Total runs: 10
Success rate: 20%

Prompt

Tokens: 349

def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it, 
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input: 
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input: 
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5
    
    Example 3:
        Input: 
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it, 
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input: 
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input: 
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5
    
    Example 3:
        Input: 
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """return sum([math.ceil(sum(arr)/capacity) for arr in grid])

Unit tests

def check(candidate):


    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
    assert candidate([[0,0,0], [0,0,0]], 5) == 0, "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, "Error"
    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, "Error"

Runs

❌ Run 1

Start time: 2023-07-18 17:09:31
Duration: 2.79s
Completion tokens: 52
Result: Fail

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / capacity)
    return num_buckets

❌ Run 2

Start time: 2023-07-18 17:09:29
Duration: 2.57s
Completion tokens: 52
Result: Fail

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / capacity)
    return num_buckets

❌ Run 3

Start time: 2023-07-18 17:09:26
Duration: 2.77s
Completion tokens: 53
Result: Fail

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / capacity)
    return num_buckets

❌ Run 4

Start time: 2023-07-18 17:09:23
Duration: 2.38s
Completion tokens: 52
Result: Fail

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / capacity)
    return num_buckets

❌ Run 5

Start time: 2023-07-18 17:09:21
Duration: 2.03s
Completion tokens: 48
Result: Fail

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / capacity)
    return num_buckets

✅ Run 6

Start time: 2023-07-18 17:09:18
Duration: 2.88s
Completion tokens: 59
Result: Pass

def max_fill(grid, bucket_capacity):
    num_buckets = 0
    for row in grid:
        num_buckets += sum(row) // bucket_capacity
        if sum(row) % bucket_capacity != 0:
            num_buckets += 1
    return num_buckets

❌ Run 7

Start time: 2023-07-18 17:09:16
Duration: 2.47s
Completion tokens: 53
Result: Fail

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / capacity)
    return num_buckets

❌ Run 8

Start time: 2023-07-18 17:09:12
Duration: 4.03s
Completion tokens: 82
Result: Fail

def max_fill(grid, capacity):
    rows = len(grid)
    cols = len(grid[0])
    total_buckets = 0
    
    for row in range(rows):
        for col in range(cols):
            if grid[row][col] == 1:
                total_buckets += 1
    
    num_buckets_needed = math.ceil(total_buckets / capacity)
    return num_buckets_needed

✅ Run 9

Start time: 2023-07-18 17:09:09
Duration: 2.5s
Completion tokens: 56
Result: Pass

def max_fill(grid, capacity):
    num_buckets = 0
    for row in grid:
        num_buckets += sum(row) // capacity
        if sum(row) % capacity != 0:
            num_buckets += 1
    return num_buckets

❌ Run 10

Start time: 2023-07-18 17:09:06
Duration: 2.84s
Completion tokens: 55
Result: Fail

def max_fill(grid, bucket_capacity):
    num_buckets = 0
    for row in grid:
        for well in row:
            if well == 1:
                num_buckets += math.ceil(well / bucket_capacity)
    return num_buckets