Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%
Tokens: 237
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Input: 12
Output: (4, 6)
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
"""The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Input: 12
Output: (4, 6)
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
"""def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)def check(candidate):
# Check some simple cases
assert candidate(123) == (8, 13)
assert candidate(12) == (4, 6)
assert candidate(3) == (1, 2)
assert candidate(63) == (6, 8)
assert candidate(25) == (5, 6)
assert candidate(19) == (4, 6)
assert candidate(9) == (4, 5), "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate(1) == (0, 1), "This prints if this assert fails 2 (also good for debugging!)"Start time: 2023-07-18 18:12:33
Duration: 21.03s
Completion tokens: 185
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]:
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:12:14
Duration: 19.3s
Completion tokens: 197
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]:
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:11:59
Duration: 15.03s
Completion tokens: 212
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]:
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:11:36
Duration: 22.84s
Completion tokens: 235
Result: Pass
def even_odd_palindrome(n):
def is_palindrome(num):
return str(num) == str(num)[::-1]
even_count = 0
odd_count = 0
for i in range(1, n+1):
if is_palindrome(i):
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:11:19
Duration: 16.89s
Completion tokens: 195
Result: Pass
def even_odd_palindrome(n):
def is_palindrome(num):
return str(num) == str(num)[::-1]
even_count = 0
odd_count = 0
for i in range(1, n + 1):
if is_palindrome(i):
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:11:05
Duration: 13.73s
Completion tokens: 178
Result: Pass
def even_odd_palindrome(n):
def is_palindrome(num):
return str(num) == str(num)[::-1]
even_count = 0
odd_count = 0
for i in range(1, n+1):
if is_palindrome(i):
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:10:49
Duration: 16.48s
Completion tokens: 197
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]:
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:10:34
Duration: 14.81s
Completion tokens: 184
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]:
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:10:24
Duration: 10.24s
Completion tokens: 120
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]: # check if the number is a palindrome
if i % 2 == 0: # check if the number is even
even_count += 1
else: # the number is odd
odd_count += 1
return (even_count, odd_count)Start time: 2023-07-18 18:10:10
Duration: 13.29s
Completion tokens: 184
Result: Pass
def even_odd_palindrome(n):
even_count = 0
odd_count = 0
for i in range(1, n+1):
if str(i) == str(i)[::-1]:
if i % 2 == 0:
even_count += 1
else:
odd_count += 1
return (even_count, odd_count)