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需求建议:分数和难度成正相关 #69

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iotang opened this issue May 10, 2019 · 1 comment

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iotang commented May 10, 2019

墙裂建议获得的分数和难度成正相关

this.score = Math.ceil(Math.pow(window.cacheBallSpeed, 3) / 3.00)

iotang added the enhancement label

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kasuganosoras commented May 11, 2019

Good idea

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