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popRange
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#!/usr/bin/env python
#
# Copyright (c) 2016, 2017 Timothy Savannah All Rights Reserved
# under terms of the GPL version 2. You should have recieved a copy of this with distribution,
# as LICENSE. You may also find the full text at https://github.com/kata198/popLines/LICENSE
#
# This program turns files into queues. You can pop off a range of lines from a file
# So your file can contain a list of items to process, and you can use this to pop off that queue.
#
#
# You can also peek (not modify the source) with "--peek"
#vim: set ts=4 sw=4 expandtab
import os
import sys
from PopLines import popRange
def printUsage():
sys.stderr.write('''Usage: popRange (Options) [start] [stop] (?step) [filename]
Options:
--peek Perform the operation, but don't modify the source file
Where step is optional (if omitted, assumed 1).
Start and stop are 1-origin line numbers that form an inclusive range.
The values can be negative, which represents number of lines from the last line ( -1 is last line, -2 is second-to-last...)
Step is the period, so a step of 1 is every element, 2 is every other...
Examples:
popRange 1 -1 ,2 babies.txt > everyOtherBaby.txt
popRange 3 5 items.txt > itemsThreeFourAndFive.txt
''')
if __name__ == '__main__':
args = sys.argv[1:]
if '--help' in args:
printUsage()
sys.exit(1)
if '--peek' in args:
saveChanges = False
args.remove('--peek')
else:
saveChanges = True
if len(args) not in (3, 4):
sys.stderr.write('Wrong number of arguments.\n\n')
printUsage()
sys.exit(1)
start = args[0]
stop = args[1]
if len(args) > 3:
step = args[2]
else:
step = 1
try:
start = int(start)
stop = int(stop)
step = int(step)
except:
sys.stderr.write('Invalid range paramater. Should be one-origin integers.\n\n')
printUsage()
sys.exit(1)
filename = args[-1]
if not os.path.exists(filename):
sys.stderr.write('No such file: %s\n' %(filename,))
sys.exit(2)
if not os.path.isfile(filename):
sys.stderr.write('Not a file: %s\n' %(filename,))
sys.exit(2)
try:
output = popRange(start, stop, step, filename, saveChanges)
except Exception as e:
sys.stderr.write('Error: %s\n' %(str(e,)))
#raise e
sys.exit(2)
if len(output) > 0:
sys.stdout.write('\n'.join(output))
sys.stdout.write('\n')