Given an integer columnNumber
, return its corresponding column title as it appears in an Excel sheet.
For example:
A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28 ...
Example 1:
Input: columnNumber = 1 Output: "A"
Example 2:
Input: columnNumber = 28 Output: "AB"
Example 3:
Input: columnNumber = 701 Output: "ZY"
Constraints:
1 <= columnNumber <= 231 - 1
class Solution:
def convertToTitle(self, columnNumber: int) -> str:
res = []
while columnNumber:
columnNumber -= 1
res.append(chr(ord('A') + columnNumber % 26))
columnNumber //= 26
return ''.join(res[::-1])
class Solution {
public String convertToTitle(int columnNumber) {
StringBuilder res = new StringBuilder();
while (columnNumber != 0) {
--columnNumber;
res.append((char) ('A' + columnNumber % 26));
columnNumber /= 26;
}
return res.reverse().toString();
}
}
function convertToTitle(columnNumber: number): string {
let res: string[] = [];
while (columnNumber > 0) {
--columnNumber;
let num: number = columnNumber % 26;
res.unshift(String.fromCharCode(num + 65));
columnNumber = Math.floor(columnNumber / 26);
}
return res.join('');
}
public class Solution {
public string ConvertToTitle(int columnNumber) {
StringBuilder res = new StringBuilder();
while (columnNumber != 0) {
--columnNumber;
res.Append((char) ('A' + columnNumber % 26));
columnNumber /= 26;
}
return new string(res.ToString().Reverse().ToArray());
}
}